Question 744755
Prove:
{{{ log( 1/c, (x) ) = log( c, (1/x) ) }}}
I will say that
{{{ a =  log( 1/c, (x) ) }}}
{{{ b = log( c, (1/x) ) }}}
Now I can say
(1) {{{ ( 1/c )^a = x }}}
(2) {{{ c^b = 1/x }}}
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(2) {{{ 1/( c^b ) = x }}}
Now I can say
{{{ 1/( c^b) = ( 1/c)^a }}}
This is the same as
{{{ ( 1/c )^b = ( 1/c )^a }}}
{{{ a = b }}}
{{{ log( 1/c, x ) = log( c, 1/x ) }}}