Question 744694
-11x^2+12x - 6 = 0
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Answers:
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A) x ={-6 +- i[SQRT(60)]}/11 
B) x = {-6 +- i[SQRT(30)]}/-11 
C) x = {6 +- i[SQRT(12)]}/6 
D) x = {-6 +- i[SQRT(22)]}/-11 
E) x = {-11 +- i} /6 
F) x = {11 +- i} /-6 
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What I did first is to insert the question into the quadratic formula, with -11, 12 and -6 as a, b and c. 
(-12 ± √144 - 264) / (-22)
Which turns into
(-12±√-120) / -22
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But now I'm stuck. Could I have some help please?
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(-12±√-120) / -22  You were almost done.
= {{{(6 + i*sqrt(30))/11}}}
= {{{(6 - i*sqrt(30))/11}}}
--> C
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*[invoke solve_quadratic_equation -11,12,-6]