<PRE><B>Question 64853</B>
&lt;pre&gt;&lt;font face = &quot;french script MT&quot; size = 9&gt;&lt;b&gt;Urgent please help!!!

 -1 + 41log&lt;sub&gt;3&lt;/sub&gt;(-3x) = 7

Isolate the log term by adding 1
to both sides:

     41log&lt;sub&gt;3&lt;/sub&gt;(-3x) = 8

Divide both sides by 41

       log&lt;sub&gt;3&lt;/sub&gt;(-3x) = 8/41

Use this rule of logarithms:

The logarithm equation log&lt;sub&gt;B&lt;/sub&gt;A = C can be 
rewritten equivalently as the exponential
equation A = B&lt;sup&gt;C&lt;/sup&gt;

           -3x = 3&lt;sup&gt;8/41&lt;/sup&gt;

Divide both sides by -3

             x = (3&lt;sup&gt;8/41&lt;/sup&gt;) ÷ (-3) 

             x = -(3&lt;sup&gt;8/41&lt;/sup&gt;)÷(3&lt;sup&gt;1&lt;/sup&gt;)

Subtract exponents of 3:

             x = -3&lt;sup&gt;8/41-1&lt;/sup&gt;

             x = -3&lt;sup&gt;8/41-41/41&lt;/sup&gt;

             x = -3&lt;sup&gt;-33/41&lt;/sup&gt;

             x = -1/(3&lt;sup&gt;33/41&lt;/sup&gt;) 
  
             x = -.413024273, approximately

Edwin&lt;/pre&gt;&lt;/font&gt;&lt;/b&gt; </PRE>