Question 744574
the present age of a father is equal to the sum of ages of his 5 children.
f = a+b+c+d+e
:
 12 years hence the sum of ages of his children will be twice the age of their father.
a+12 + b+12 + c+12 + d+12 + e+12 = 2(f+12)
 a+b+c+d+e + 60 = 2f + 24
Replace a+b+c+d+e with f
f + 60 = 2f + 24
60 - 24 = 2f - f
36 = f
:
find the present age of the father. He's 36 yrs old