Question 744487
a) 5^(2x) + 5^(x) - 6 = 0 (hint let y = 5^(x) 
.
We Let y = 5^x
if so, we can rewrite:
5^(2x) + 5^(x) - 6 = 0
AS
y^2 + y - 6 = 0
now, we factor :
(y+3)(y-2) = 0
y = {-3, 2)
.
But, we still need to find x:
since
y = 5^x
we substitute each value of y to find x:
-3 = 5^x
{{{log(5,-3) = x }}}
since we can't take the log of a negative value we throw out this solution.
.
2 = 5^x
{{{log(5,2) = x }}}
{{{log(2)/log(5) = x }}}
0.431 = x