Question 744484
log(base 5)x+2 + log(base 5) x-2 - log(base 5)4 = log(base 5)3


log(base 5)((x+2)(x-2)) - log(base 5)4 = log(base 5)3
 

log(base 5)(((x+2)(x-2))/4) = log(base 5)3


common base

{{{((x+2)(x-2))/4=3}}}


{{{x^2-4=12}}}


{{{x^2=12+4}}}

{{{x^2=16}}}

x=+/-4

therefore x=4