Question 744441
{{{9 -3sqrt(3)-3}}}

r= {{{3sqrt(3)/9}}}=>{{{1/sqrt(3))}}}


{{{r<1}}}


{{{tn= ar^(n-1)}}}

a=9, r= sqrt(1/3)

{{{t4=9*(1/sqrt(3))^(4-1)}}}


{{{t4=9*(1/sqrt(3))^(3)}}}

{{{t4= 9*(1/3sqrt(3))}}}

{{{t4=sqrt(3)}}}

you find the 5th and 6th in the same way