Question 744302
{{{log(4,(8x-9))- log(4,(x+1))}}} = 1
we write this over a single log, subtraction means divide:
{{{log(4,((8x-9)/(x+1)))}}} = 1
The exponent equiv
{{{((8x-9)/(x+1))}}} = {{{4^1}}}
or just
{{{((8x-9)/(x+1))}}} = 4
multiply both sides by (x+1)
8x - 9 = 4(x + 1)
8x - 9 = 4x + 4
8x - 4x = 4 + 9
4x = 13
x = 13/4
x = 3.25