Question 744294
Find the equation for the hyperbola with foci (4,6) and (-8,6) and a transverse axis length of 8
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Given hyperbola has a horizontal transverse axis.
Its standard form of equation: {{{(x-h)^2/a^2-(y-k)^2/b^2=1}}}, (h,k)=(x,y) coordinates of center.
For given hyperbola:
center: (-2, 6)
length of transverse axis=8=2a
a=4
a^2=16
c=6 (distance from center to foci on the transverse axis)
c^2=36
c^2=a^2+b^2
b^2=c^2-a^2=36-16=20
Equation of given hyperbola:
{{{((x+2)^2/16)-((y-6)^2/20)=1}}}