Question 744146
You could switch radians to degrees, but that would not help if the answer is expected in radians.
 
MATCHING JUST SINE:
The sine of supplementary angles is the same. For example,
{{{sin(30^o)=sin(180^0-30^o)=sin(150^0)=0.5}}}
and all the angles differing by {{{k*360^o}}} from those have the same sine too.
 
{{{2pi}}} radians corresponds to {{{360^o}}},
{{{pi}}} radians corresponds to {{{180^o}}}, and
{{{pi/2}}} radians corresponds to {{{90^o}}}.
{{{pi/2<2.3<pi}}} so an angle of 2.3 radians is in the second quadrant.
There is a supplementary first quadrant angle that has the same sine: {{{pi-2.3}}}.
All the angles that differ from those by a whole number of turns (clockwise or counterclockwise) have the same sine too, so adding or subtracting {{{2pi}}} to the previous answers gives you more answers:
{{{2pi+2.3}}}, {{{2.3-2pi}}}, {{{3pi-2.3}}}, {{{-2.3-pi}}}
If you want to translate 2.3 radians to degrees, knowing that {{{pi}}} radians corresponds to {{{180^o}}}, you can calculate that 2.3 radians corresponds to
{{{2.3*180^o/pi}}}= approximately {{{131.8^o}}} (rounding to the nearest {{{0.1^o}}})
 
IF YOU HAVE TO MATCH ALL TRIG RATIOS:
The angles that have all the same trigonometric ratios are the co-terminal angles, those that differ by multiples of {{{360^o}}} or {{{2pi}}}.
So, for an angle {{{alpha}}} (in degrees), all angles measuring {{{alpha+k*360^o}}} for some positive or negative integer {{{k}}} have all the same trigonometric  ratios.
Thinking in radians, for an angle {{{theta}}} (in radians), all angles measuring {{{theta +k*2pi}}} for some positive or negative integer {{{k}}} have all the same trigonometric  ratios.