<PRE><B>Question 744064</B>
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Use the definition of logarithms and the convention that if the base is not specified, base 10 is assumed.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y = \log_b(x) \ \ \Rightarrow\ \ b^y = x]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 10^{2.5}]


Use your calculator and round as instructed.


If you use the convention that *[tex \LARGE \log] with an unspecified base means the log to the base *[tex \LARGE e], that is *[tex \LARGE \log] means *[tex \LARGE \ln], then replace 10 with *[tex \LARGE e] in the above.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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