Question 64797
{{{P(x) = (x^2 - 25)(x + 1)^3}}}
The first bracket factorises to give {{{(x+5)(x-5)}}}
{{{P(x) = (x+5)(x-5)(x + 1)^3}}}
So the zeroes are -5 (once), +5 (once), and -1 (three times)