Question 8241
I will assume you mean the equation of the line that has a slope of 1/4 and passes through the point (3,1).
The equation of the slope of a line is the rise (change in y) over the run (change in x). So, we have
{{{slope = (y[2]-y[1])/(x[2]-x[1])}}} where one point is (x[1],y[1]) and the other is (x[2], y[2])
You know the slope (1/4) and you know one point (3,1) so you put these values in the equation of the slope and rearrange to get the slope-intercept form.
{{{1/4=(1-y)/(3-x)}}}
{{{3-x=4-4y}}} 
{{{-1-x=-4y}}}
{{{4y=x+1}}}
{{{y=(1/4)x+1/4}}}