Question 743729
Four consecutive even integers are
2n
2n+2
2n+4
2n+6


{{{5(2n)-2*(2n+4)}}}------twice the third integer subtracted from five times the first


{{{18+(2n+2)+(2n+6)}}}--------18 more than the sum of the second and the fourth integer


{{{highlight(5(2n)-2*(2n+4)=18+(2n+2)+(2n+6))}}}
Simplify and solve for n.
Use n found to compute each of the integers.