Question 743643
L-list price
S-sale price
D-discount

D-8% of L so

{{{D=0.08*L}}}

The sale price is how much it costs after the discount:
{{{L - D = S}}}

Now we substitute in the known values and solve for L:
{{{L-0.08L=18.40}}}
{{{0.92L=18.40}}}
{{{(0.92L)/0.92=18.40/0.92}}}

so L=$20.00