Question 743492
Prove: 
Log(base 5) 7 - Log (base 25) 7 = Log (base 25)7
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log(7)/log(5) = 2log25(7)
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log(7)/log(5) = 2log(7)/log(5^2)
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log(7)/log(5) = 2[log(7)/2log(5)]
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log(7)/log(5) = log(7)/log(5)
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Cheers,
Stan H.
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