Question 64774
{{{(4x-3y)^2}}}
{{{(4x-3y)(4x-3y)}}}
Multiply the 4x by each of the terms in the second bracket then multiply (-3y) by each of the terms in the second bracket.
{{{4x*4x-3y*4x-3y*4x-3y*(-3y)}}}
{{{16x^2-12xy-12xy+9y^2}}}
{{{16x^2-24xy+9y^2}}}