Question 743558
2log(base4)X-log(base4)(3X-4)=1/2
log(base4)X^2-log(base4)(3X-4)=1/2
log(base4)X^2/(3X-4)=1/2
X^2/(3X-4)=4^(1/2)
X^2/(3X-4)=2
X^2=2(3X-4)
X^2=6X-8
X^2-6X+8=0
(X-2)(X-4)=0
X = {2, 4}