Question 743525
<pre>
Here's a deck of 52 cards:

<font color = "red">
 
A&#9829;   2&#9829;   3&#9829;   4&#9829;   5&#9829;   6&#9829;   7&#9829;   8&#9829;  9&#9829;  10&#9829;  J&#9829;  Q&#9829;  K&#9829; 
A&#9830;   2&#9830;   3&#9830;   4&#9830;   5&#9830;   6&#9830;   7&#9830;   8&#9830;  9&#9830;  10&#9830;  J&#9830;  Q&#9830;  K&#9830;</font>
A&#9824;   2&#9824;   3&#9824;   4&#9824;   5&#9824;   6&#9824;   7&#9824;   8&#9824;  9&#9824;  10&#9824;  J&#9824;  Q&#9824;  K&#9824;  
A&#9827;   2&#9827;   3&#9827;   4&#9827;   5&#9827;   6&#9827;   7&#9827;   8&#9827;  9&#9827;  10&#9827;  J&#9827;  Q&#9827;  K&#9827; 

The probability of getting a club or a red queen is the probability of
getting any one of these 15 cards:

<font color = "red">
                                                    Q&#9829; 
                                                    Q&#9830;</font>
</font>  
A&#9827;   2&#9827;   3&#9827;   4&#9827;   5&#9827;   6&#9827;   7&#9827;   8&#9827;  9&#9827;  10&#9827;  J&#9827;  Q&#9827;  K&#9827;

So the desired probability is 15 out of the 52 or {{{15/52}}}

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The probability of getting a card that is not a face card is the probability of
getting any one of these 40 cards:

<font color = "red">
 
A&#9829;   2&#9829;   3&#9829;   4&#9829;   5&#9829;   6&#9829;   7&#9829;   8&#9829;  9&#9829;  10&#9829;   
A&#9830;   2&#9830;   3&#9830;   4&#9830;   5&#9830;   6&#9830;   7&#9830;   8&#9830;  9&#9830;  10&#9830;  </font>
A&#9824;   2&#9824;   3&#9824;   4&#9824;   5&#9824;   6&#9824;   7&#9824;   8&#9824;  9&#9824;  10&#9824;    
A&#9827;   2&#9827;   3&#9827;   4&#9827;   5&#9827;   6&#9827;   7&#9827;   8&#9827;  9&#9827;  10&#9827;

So the desired probability is 40 out of the 52 or {{{40/52}}} which
reduces to {{{10/13}}}

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The probability of getting a card that is neither a face card nor a number
is the probability of getting any one of these 4 aces:

<font color = "red">
 
A&#9829;   
A&#9830; </font>
A&#9824;           
A&#9827;

So the desired probability is 4 out of the 52 or {{{4/52}}} which
reduces to {{{1/13}}}

--------------------------------------------------------------      

Edwin</pre>