<PRE><B>Question 64770</B>
Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
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Consecutive even integers: 2x, 2x+2,2x+4
EQUATION:
(2x+4)^2=(2x+2)^2+76
4x^2+16x+16 = 4x^2+8x+4+76
8x=64
x=8
1st number: 2x=16
2nd: 18
3rd: 20
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Cheers,
Stan H.</PRE>