Question 743228
How do I factor b to the third power plus 49b completely. I have broke down into prime factors giving me b*b*b+7*7*b. This gives me b squared plus 49. Please advise if I am doing this polynomial correctly.
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You're doing it correctly.
The only common factor is b
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{{{b^3 + 49b = b*(b^2 + 49)}}}
All you can do.