Question 743078
1. solve the following equation 
ln(5x+1)=2-ln(2x-3) 
ln(5x+1)+ln(2x-3)=2
ln[(5x+1)(2x-3)]=2
convert to exponential form
e^2=(5x+1)(2x-3)
e^2=(10x^2-13x-3)
10x^2-13x-3-e^2=0
10x^2-13x-10.389=0
solve for x using quadratic formula
x≈-0.5589 (reject, (5x+1)>0)
or 
x≈1.8589