Question 743039
{{{ 11x+8=(x+2)(3x+4) }}}

Multiply brackets on RHS

{{{ 11x+8= 3x^2+6x+4x+8 = 3x^2+10x+8  }}}

Subtract 11x-8 from both sides gives {{{ 3x^2 - x = 0 }}}

hence x( 3x-1 ) = 0

Hence x=0 or (3x-1)=0

If 3x-1=0 then {{{ x = 1/3 }}}

Solutions {{{ x=1/3 }}} , {{{ x=0 }}}