Question 742947
What is the solution to sin squared x+2sinx-2 ?
{{{sin^2(x)+2sin(x)-2=0}}}
solve for sin(x) by quadratic formula
a=1, b=2,c=-2
{{{sin(x) = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{sin(x) = (-2 +- sqrt( 4+8 ))/(2) }}}
{{{sin(x) = (-2 +- sqrt(12 ))/(2) }}}
sin(x)≈-2.72 (reject, (-1≤sinx≤1))
or
sinx≈0.732
x≈47.5º