Question 742805
3x^2 - 2x + 4 = 18 - 3x
3x^2 + x = 14  (this is ok)
However, when solving a "quadratic" (polynomial of degree 2 -- which, this is) always set one side to zero:
3x^2 + x = 14
3x^2 + x - 14 = 0
here, you factor if possible otherwise you can resort to the "quadratic formula".
.
I'll factor.
3x^2 + x - 14 = 0
to factor, you'd like to rewrite the middle term so that the coefficients add to give you 'b' (1) AND multiplies to give you ac(3*(-14)):
3x^2 + 7x - 6x - 14 = 0
notice (7-6) gives you 'b' and multiplies to give you -42
now, we group:
(3x^2 + 7x) - (6x + 14) = 0
x(3x + 7) - 2(3x + 7) = 0
(3x + 7)(x-2) = 0
x = { -7/3, 2}