Question 742603
a) log(base2)3 + log(base2)5)
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= log2(3*5) = log2(15)
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b) 2log(base2)3 + log(base2)5
= log2(3^2) + log2(5)
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= log2(9*5)
-------
= log2(45)
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c) log(base5)2 + log(base5)3 - log(base5)7
= log5[2*3/7] 
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= log5[6/7]
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Cheers,
Stan H.