Question 742472
We are given

What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the largest integer? 

let 3 consecutive positive integers be i, i+1, i+2

then we have,

i*(i+1) = 5*(i+2)-5
 
now, we multiply and simplify

i^2+i = 5i+10-5

regroup and set equal to 0

i^2-4i-5=0

factor this expression into

(i-5)*(i+1) = 0

therefore i=5 or -1, we choose i=5 since our integers are to be positive

and our solution is the integers 5, 6, 7