Question 742400
if log m + log n = log (m+n ), find m in terms of n
we can write this as
log(mn) = log(m+n)
therefore
mn = m + n
subtract m from both sides
mn - m = n
Factor out m
m(n-1) = n
divide both sides by (n-1)
m = {{{n/((n-1))}}}