Question 742380
b = rate of big pipe
s = rate of small pipe
e = rate for outlet pipe, which empties the tank
Rates are in TANK per HOUR, and rates are additive.  {{{e<0}}} because it works in the opposite direction from b and s.  


{{{b = 1/1=1 }}}
{{{s = 1/6}}}
{{{e = -1/7}}}


All three pipes begin operating together at a time the tank is initially empty.  How much of the tank will be filled in 0.98 hours?
{{{R*h=j}}}, where R is the combined rates of the three pipes, h is time in hours, and j is the amount of the job of filling the tank (which we expect to be positive).


{{{(b+s+e)*h=j}}}
{{{(b+s+e)*0.98=j}}}, find j.
{{{highlight((1+1/6+(-1/7))*(0.98)=j)}}}
{{{(1+1/6-1/7)*(0.98)=j}}}
{{{((42+7-6)/42)*(0.98)=j}}}
{{{highlight((43/42)(0.98)=j)}}}


{{{j=1.00}}} to the nearest hundredth place.  This did not render as needed, so,..
{{{j=1.00____}}} to the nearest hundredth place.  This system does not render the way it should.  That should appear as, "One point zero zero".