<PRE><B>Question 742331</B>
Given the equation of a basic graph and describe a sequence of transformation that can be used to find the graph of y=-|2x-3| DONOT GRAPH .
Basic graph equation: y = |x|
Transformations:
1st: horizontal stretch by factor of 2
2nd: shift 3 units to the right
3rd: reflect in the x-axis
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10.)Calculate an equation for the circle for which the segment represent PQ is a diameter
P=(-3,1) , Q=(5,6)
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Find Center (x,y)
x = (-3+5)/2 = 1
y = (6+1)/2 = 3.5
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Find the Radius:
r = sqrt[(-3-1)^2 + (1-3.5)^2] = sqrt[16+6.25] = sqrt(22.25)
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Equation:
(x+3)^2 + (Y-1)^2 = 22.25
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Cheers,
Stan H.

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