Question 742189
2*log(x-1)=2+log(100)
2log(x-1)-log(100)=2
log(x-1)^2-log(100)=2
log((1/100)(x-1)^2)=2


What you do next depends on what the base is.  Assuming you are using some base, b, you would transform:

{{{b^2=(1/100)*(x-1)^2}}}
Also, looking carefully at the factor on the right side,
{{{b^2=((x-1)/10)^2}}}
Seeing that, the base must be equal to the expression shown in the same position on the rightside:
{{{b=(x-1)/10}}}.


From this, {{{10b=x-1}}}
{{{highlight(x=10b+1)}}}  You need to know the value of b in order to find anything further.