Question 742294
4x+3y=15 and 5x-2y=13.


" tried: 4x+3y=15 subtracted 4 from both sides and then divided it by 3 to get the y by its self and then I plugged it into the second equation but "


First Equation: {{{4x+3y=15}}}
{{{3y=15-4x}}}
{{{y=15/3-4x/3=5-(4/3)x}}}


Second Equation: {{{5x-2(y)=13}}}
{{{5x-2(5-4x/3)=13}}}, the substitution
{{{5x-10+8x/3=13}}}
{{{5x+8x/3-10=13}}}
{{{(5+8/3)x=13+10}}}
{{{(15/3+8/3)x=23}}}
{{{(23/3)x=23}}}
{{{x=23*(3/23)}}}
Final Answer for x: {{{highlight(x=3)}}}