Question 742270
 log( 9, 1/27 ) = log(1/27)/log(9) = -3/2 
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 log ( 9, sqrt( 3 ) ) = log(sqrt(3))/log(9) = (1/2)/2 = 1/4
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 log ( 8, root( 3, 2 )) = 
log8(2^(1/3)) = log(2^(1/3))/log(2^3) = (1/3)/3 = 1/9
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 log ( 3, root( 3, 1/9 ))}}}
log3[(1/9)^(1/3)] = log(1/9)^(1/3)/log(3) = (1/3)log(1/9)/log(3)
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= (1/3)*(-2)/1 = -1/6
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Cheers,
Stan H.
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