Question 742187
Looking at question a:


a) log3+log y = log(x+2) - logx
log(3y)=log((x+2)/x)
Arguments must be equal.
3y=(x+2)/x
{{{y=(x+2)/(3x)}}}


Domain is {{{x<0}}} and {{{x>0}}}.
x must be equal 0, becaus denominator of 3x=3*0=0 and division by 0 is not allowed.