Question 742113
As you figured it, the question is how many ways can you choose a teamm of 11 from the 22 people available, because once you pick one team, the other team is already determined.
{{{C(m,n)=m!/(n!(m-n)!)}}}
When {{{m=22}}} and {{{n=11}}}, {{{m-n=11}}} and
{{{C(22,11)=22!/(11!11!)=705432}}}