Question 64664
 x=5y-1 [substitute "5y-1" for x in the second equation]
2(5y-1)+5y=-32  [simplify]
10y-2+5y=-32 
15y-2=-32 [solve for y]
15y=-32+2
15y=-30
y=-2
.
check by plugging y into either equation and solve for x
x=5y-1
x=5(-2)-1
x=-10-1
x=-11
.
-11=5(-2)-1
-11=-10-1
-11=-11 [checks out]