Question 741920
Find an equation for the hyperbola described.
Vertices at (2,0) and (-2,0); foci at (4,0) and (-4,0)
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Given hyperbola has a horizontal transverse axis:
Its standard form of equation: {{{(x-h)^2/a^2-(y-k)^2/b^2=1}}}, (h,k)=(x,y) coordinates of center:
For given hyperbola:
center:(0,0)
a=2 (distance from center to vertices)
a^2=4
c=4 (distance from center to foci)
c^2=16
c^2=a^2+b^2
b^2=c^2-a^2=16-4=12
Equation:
{{{x^2/4-y^2/12=1}}}