Question 741657
Good start BUT not thorough enough.


Case: {{{x+3>=0}}} and {{{x+1>=0}}}
{{{5(x+3)-2x-2=4}}}
.
find {{{x=-3}}}


Case: {{{x+3<0}}} and {{{x+1<0}}}
{{{-5(x+3)+2(x+1)=4}}}
.
{{{x=-3}}}


Case: {{{x+3>=0}}} and {{{x+1<0}}}
{{{5(x+3)+2(x+1)=4}}}
{{{5x+15+2x+2=4}}}
{{{7x+17=4}}}
{{{7x=4-17}}}
.
{{{x=-(13/7)}}}


Case: {{{x+3<0}}} and {{{x+1>=0}}}
{{{-5(x+3)-2(x+1)=4}}}
.
{{{x=-3}}}


Solutions:  {{{x = -3}}} or {{{x=-(13/7)}}}