Question 741570
solve m+n over m-n / 3m+3n over m^-n^ 
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[(m+n)/(m-n)]/[(3(m+n)/(m-n)]
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= [(m+n)/(m-n)]*[(m-n)/(3(m+n)]
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Cancel factors common to numerator and denominator to get:
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= 1/3
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Cheers,
Stan H.
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