Question 741517

1- what is te value of {{{x}}} in the equation {{{13x-2(x+4)=8x+10}}}

{{{13x-2(x+4)=8x+10}}}..first multiply {{{-2(x+4)}}}

{{{13x-2*x+(-2)*4=8x+10}}}

{{{13x-2x-8=8x+10}}}

{{{11x-8=8x+10}}}....add {{{-8x}}} to the both sides

{{{11x-8-8x=8x-8x+10}}}

{{{3x-8=10}}}...add {{{8}}} to the both sides

{{{3x-8+8=10+8}}}

{{{3x=18}}}

{{{x=18/3}}}

{{{highlight(x=6)}}}


2- the sum of 
{{{3x^2+4x-2}}} and {{{x^2-5x+3}}} is...

{{{3x^2+4x-2+x^2-5x+3}}}...rearrange, put like terms next to each other

{{{3x^2+x^2+4x-5x+3-2}}}

{{{highlight(4x^2-x+1)}}}



3- the expression 
{{{(3x^2+2xy+7)-(6x-4xy+3)}}} is equivalent to

{{{(3x^2+2xy+7)-(6x-4xy+3)=3x^2+2xy+7-6x+4xy-3=highlight(3x^2+6xy-6x+4)}}}


4- the expression

{{{ (x^2-5x-2)-(-6x^2-7x-3)}}} is equivalent to...


{{{(x^2-5x-2)-(-6x^2-7x-3) =x^2-5x-2+6x^2+7x+3}}}


{{{(x^2-5x-2)-(-6x^2-7x-3) =highlight(7x^2+2x+1)}}}