Question 741511
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From 8 am to 2 pm is 6 hours, so Susan drove at *[tex \LARGE x] miles per hour for 6 hours and therefore travelled *[tex \LARGE 6x] miles.  Carol only drove for 5 hours, because she left one hour later.  But she travelled at *[tex \LARGE x\ +\ 7] miles per hour, so she travelled *[tex \LARGE 5x\ +\ 35] miles.  Those two distances have to be equal, so set them equal and solve for *[tex \LARGE x].  Once you know *[tex \LARGE x], Susan's speed, you can add 7 to get Carol's speed.  Calculate *[tex \LARGE 6x] to get the distance traveled.  Then calculate *[tex \LARGE 5(x + 7)] to check your work.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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