Question 741336


{{{w^2+30w+81}}}...write {{{30w}}} as {{{3w+27w}}}

={{{w^2+3w+27w+81}}}...group first two and second two terms together

={{{(w^2+3w)+(27w+81)}}}..factor

={{{w(w+3)+27(w+3)}}}

={{{(w+3)(w+27)}}}