Question 736723
n=ones 
t=tens
f=fives
y=fifties

n+10t+5f+50y=1500
10n=f
2t=y
we only have three equations with four unknowns
we can limit the numbers
150>t>0
30>y>0
1500>n>0
300>f>0
y must be even 
there are now only 15 possible values for y
n<f
so
300>n>0
but f <300
so 30>n
and 
t<15
from trial and error
n = 10 and f = 100 and t = 9 and y = 18
check
10*1+100*5+9*10+18*50
10+500+90+900=1500
1500=1500
ok