<PRE><B>Question 741265</B>
-(x+6)^3(x+4)^2(x+2)^5(x-3).sketch graph..how?????
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End Behavior:
Because of the negative on the left, the graph starts in QII and ends in QIV.
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Mark the x-values -6,-4,-2,3 on the x axis
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Because of (x+6)^3 the graph passes through the axis at x = -6
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Because of (x+4)^2 the graph touches but does not pass thru at x = -4
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Because of (x+2)^5 the graph passes thru the axis at x = -2
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Because of (x-3) the graph passes thru the axis at x = 3
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Cheers,
Stan H.
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