Question 741214
  (2n)!/ 3!(2n-3)! and n!/ 2!(n-2)! are in the ratio 44:3,find n.




{{{(((2n)!/3!(2n-3)!)/(n!/2!(n-2)!))=44/3}}}




{{{(((2n)!/3!(2n-3)!)*(2!(n-2)!/n!))=44/3}}}



{{{(((2n)(2n-1)(2n-2)(2n-3)!)/(3*2(2n-3)!))*(2!(n-2)!/(n(n-1)(n-2)!)))=44/3}}}


{{{(((2n)(2n-1)(2n-2))/(3))*(1/(n(n-1)))=44/3}}}


{{{((2n-1)(2n-2))/(n-1)=22}}}


simplify you will get 

2(2n-1)=22

2n-1=11
2n=12
n=6