Question 741179
Let {{{ x }}} = gallons of skim milk to be added
{{{ .06*50 = 3 }}} = gallons of butterfat in 50 gallon barrel
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{{{ 3 / ( 50 + x ) = .03 }}}
{{{ 3 = .03*( 50 + x ) }}}
{{{ 3 = 1.5 + .03x }}}
{{{ .03x = 1.5 }}}
{{{ x = 50 }}}
50 gallons of skim milk must be added
check:
{{{ 3 / ( 50 + x ) = .03 }}}
{{{ 3 / ( 50 + 50 ) = .03 }}}
{{{ 3/100 = .03 }}}
{{{ .03 = .03 }}}
OK