Question 740086
Given Log base of 3 of 4 is about 1.26 and the log base of 3 of 28 is about 1.77
1.) the log base of 3 of root 7
{{{log(3,(7))}}}
{{{log(3,(28/4))}}}
{{{log(3,(28))-log(3,(4))}}}
=1.77-1.26=0.51
..
2.) the log base of 3 of 12/7
{{{log(3,(12/7))}}}
{{{log(3,(48/28))}}}
{{{log(3,(48))-log(3,(28))}}}
{{{log(3,(3*16))-log(3,(28))}}}
{{{log(3,(3*4^2))-log(3,(28))}}}
{{{log(3,(3))+2log(3,(4))-log(3,(28))}}}
≈1+2(1.26)-1.77
≈1.75
This answer does not check with a calculator because given log base of 3 of 28 is not correct.
log base of 3 of 28 ≈3.033 instead of 1.77
The correct answer will be:1+2(1.26)-3.033≈0.487 (with this correction)