<PRE><B>Question 741105</B>
A plane flies on a bearing of 230o at 350 miles per hour.  A wind is blowing from the west at 30 miles per hour.  Find the groundspeed and the final bearing of the plane in the wind.
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2 sides of the triangle are 350 &amp; 30.
The angle between the 2 sides = 270 - 230 = 40 degs
{{{GS = sqrt(350^2 + 30^3 - 2*350*30*cos(40))}}}
GS =~ 327.586 mi/hr
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angle A is between heading and ground track
GS/sin(40) = 30/sin(A)
A =~ 3.375 degs
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ground track = 230 - A = 226.6 degs

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