Question 740883
Solve the following logarithmic equation: 
log(9)(x-6)+log(9)(x+2)=1
{{{log(9,(x-6))+log(9,(x+2))=1}}}
{{{log(9,(x-6)(x+2))=1}}}
{{{log(9,(x-6)(x+2))=log(9,(9))}}}
(x-6)(x+2)=9
x^2-4x-12-9=0
x^2-4x-21=0
(x-7)(x+3)=0
x=-3 (reject, (x+2)>0)
x=7