Question 740826
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Typically, though not always, it is a good idea to allow the variable to represent the quantity you are trying to discover.  In this case, the cost of the computer.  That way, once you have solved whatever equation results from that choice and the parameters of the problem, you have your answer directly.  So, with that in mind, let *[tex \LARGE x] represent the cost of the computer.


Then we know that the freshmen have agreed to raise *[tex \LARGE \frac{x}{3}] of the money, and the sophomores have agreed to raise *[tex \LARGE \frac{x}{2}] of the money.  And finally we know that once *[tex \LARGE \frac{x}{3}] and *[tex \LARGE \frac{x}{2}] are subtracted from the cost of the computer, $400 remains to be paid by the SGA.  Therefore:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ \frac{x}{3}\ -\ \frac{x}{2}\ =\ 400]


Solve for *[tex \LARGE x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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